Z^2+3z+28=-12

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Solution for Z^2+3z+28=-12 equation: 


Simplifying
Z2 + 3z + 28 = -12

Reorder the terms:
28 + Z2 + 3z = -12

Solving
28 + Z2 + 3z = -12

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + Z2 + -28 + 3z = -12 + -28

Reorder the terms:
28 + -28 + Z2 + 3z = -12 + -28

Combine like terms: 28 + -28 = 0
0 + Z2 + 3z = -12 + -28
Z2 + 3z = -12 + -28

Combine like terms: -12 + -28 = -40
Z2 + 3z = -40

Add '-3z' to each side of the equation.
Z2 + 3z + -3z = -40 + -3z

Combine like terms: 3z + -3z = 0
Z2 + 0 = -40 + -3z
Z2 = -40 + -3z

Simplifying
Z2 = -40 + -3z

Reorder the terms:
40 + Z2 + 3z = -40 + -3z + 40 + 3z

Reorder the terms:
40 + Z2 + 3z = -40 + 40 + -3z + 3z

Combine like terms: -40 + 40 = 0
40 + Z2 + 3z = 0 + -3z + 3z
40 + Z2 + 3z = -3z + 3z

Combine like terms: -3z + 3z = 0
40 + Z2 + 3z = 0

The solution to this equation could not be determined.

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